1. calcular molesC : 37.
23 g / 12 g / mol = 3.
103 molH : 7.
81 g / 1 g / mol = 7.
81 molCl : 54.
96 g / 35.
45 g / mol = 1.
55 mol2.
Dividir entre el menor de los resultadosC : 3.
103 mol / 1.
55 mol = 2H : 7.
81 mol / 1.
55 mol = 5Cl : 1.
55 mol / 1.
55 mol = 1Fórmula empírica (FE) : C2H5Cl3.
Calcular Mm de la FEC : 2 x 12 = 24 g / molH : 5 x 1 = 5 g / molCl : 1 x 35.
45 = 35.
45 g / mol````````````````````````````````````````````````````````````` Mm = 64.
45 g / mol4.
Calcular Mm utilizando la fórmula de la LEY DE LOS GASES IDEALESV x P = n x R x T ; n = masa / Mm sustituirV x P = m / Mmx R x T despejar MmMm = (m x R x T ) / V x PDatos : R = 0.
082 (L atm / mol K)T = 150 ºC + 273 = 423 Km = 0.
922 gP = 1 atmV = 500 mL / 1000 = 0.
500 LMm = ( 0.
922 g x 0.
082 (L atm / mol K) x 423 K ) / 1 atm x 0.
500 LMm = 63.
96 g / mol (del compuesto)5.
Calcular n n = Mm compuesto / Mm FEn = 63.
96 g / mol / 64.
45 g / moln = 16.
Fórmula molecular (FM) : (C2H5Cl)n = (C2H5Cl)1 = C2H5Cl.