Necesito factorizar 64x ^ 6 - 8 A)56x ^ 6 B)8(x ^ 3 - 1)(x ^ 2 + 1) C)64(x ^ 3 - 1)(x ^ 3 - 1) D)8(2x ^ 2 - 1)(4x ^ 4 + 2x ^ 2 + 1 E)8(x ^ 2 - 1)(x ^ 4 - x ^ 2 - 1).
En resumen
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Factorizando : a * (x - y) - b * (x - y) - c * (x - y) Agrupamos el factor (x - y) (x - y) * [a - b - c] esa sería la respuesta.
X (a + b + c) + y (a + b + c) (x + y)(a + b + c) Espero que te sirva saludos ✌.
Ax + bx + cx ; factor comun x = x(a + b + c).