Avion Δ ║ ║ ║ Δ______________________Δ ∡35º ║ ∡48º ← x →║←400 - x →
la altura es el cateto opuesto para los 2 observadores es la misma
<img src="https://tex.z-dn.net/?f=tan35%3D%20%5Cfrac%7Bh%7D%7Bx%7D%20" />
h = xtan 35º
<img src="https://tex.z-dn.net/?f=tan48%3D%20%5Cfrac%7Bh%7D%7B400-x%7D%20" />
h = (400 - x)tan48º
igualamos
<img src="https://tex.z-dn.net/?f=x%5Ccdot%20%5Ctan%20%5Cleft%2835%5E%7B%5Ccirc%20%5C%3A%7D%5Cright%29%3D%5Cleft%28400-x%5Cright%29%5Ccdot%20%5Ctan%20%5Cleft%2848%5E%7B%5Ccirc%20%5C%3A%7D%5Cright%29" />
despejando x
<img src="https://tex.z-dn.net/?f=x%3D%5Cfrac%7B400%5Ctan%20%5Cleft%2848%5E%7B%5Ccirc%20%5C%3A%7D%5Cright%29%7D%7B%5Ctan%20%5Cleft%2848%5E%7B%5Ccirc%20%5C%3A%7D%5Cright%29%2B%5Ctan%20%5Cleft%2835%5E%7B%5Ccirc%20%5C%3A%7D%5Cright%29%7D%3D245.33m" />
calculamos h
h = xtan 35º = 245.
33 * 0.
70021 = 171.
78m.