Log(2x + 1) - log(2x - 1) = 2log3 - 3log2?
Log(2x + 1) - log(2x - 1) = 2log3 - 3log2.
1Velazquezlucia7luly
En resumen
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%282x%2B1%5Cright%29-%5Clog%20_%7B10%7D%5Cleft%282x-1%5Cright%29%3D2%5Clog%20_%7B10%7D%5Cleft%283%5Cright%29-3%5Clog%20_%7B10%7D%5Cleft%282%5Cright%29" /> Se suma log₁₀ (2x - 1) en ambos lados : <img src="https://tex.
Mejor respuesta
Mirandavalentin
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%282x%2B1%5Cright%29-%5Clog%20_%7B10%7D%5Cleft%282x-1%5Cright%29%3D2%5Clog%20_%7B10%7D%5Cleft%283%5Cright%29-3%5Clog%20_%7B10%7D%5Cleft%282%5Cright%29" />
Se suma log₁₀ (2x - 1) en ambos lados :
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%282x%2B1%5Cright%29%3D2%5Clog%20_%7B10%7D%5Cleft%283%5Cright%29-3%5Clog%20_%7B10%7D%5Cleft%282%5Cright%29%2B%5Clog%20_%7B10%7D%5Cleft%282x-1%5Cright%29" />
Aplicamos la propiedad de logaritmos :
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%282x%2B1%5Cright%29%3D%5Clog%20_%7B10%7D%5Cleft%289%5Cright%29-3%5Clog%20_%7B10%7D%5Cleft%282%5Cright%29%2B%5Clog%20_%7B10%7D%5Cleft%282x-1%5Cright%29" />
Aplicamos la propieda de logaritmos :
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%282x%2B1%5Cright%29%3D%5Clog%20_%7B10%7D%5Cleft%289%5Cright%29-%5Clog%20_%7B10%7D%5Cleft%288%5Cright%29%2B%5Clog%20_%7B10%7D%5Cleft%282x-1%5Cright%29" />
Se suma log₁₀ (8) a ambos lados y se aplica propiedad de logaritmos :
<img src="https://tex.z-dn.net/?f=%5Clog%20_%7B10%7D%5Cleft%28%5Cleft%282x%2B1%5Cright%29%5Ccdot%20%5C%3A8%5Cright%29%3D%5Clog%20_%7B10%7D%5Cleft%289%5Cleft%282x-1%5Cright%29%5Cright%29" />
Como LOg tienen las misma base :
<img src="https://tex.z-dn.net/?f=%5Cleft%282x%2B1%5Cright%29%5Ccdot%20%5C%3A8%3D9%5Cleft%282x-1%5Cright%29" />
Se resuelve :
<img src="https://tex.z-dn.net/?f=16x%2B8%3D18x-9" />
Nos queda entonces que :
<img src="https://tex.z-dn.net/?f=x%3D%5Cfrac%7B17%7D%7B2%7D" />.
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Log(x + 1) - logx = 1Ayudaaaaaaaa?
Espero te sirva Suerte.
1 respuesta 6