Explicación paso a paso : A.
Senx = 0, 72 calcula cosx ca = cateto adiacente co = cateto opuesto h = hipotenusa senx = cateto opuesto / hipotenusa = 72 / 100 = 18 / 25Pitágoras 25 ^ 2 = 18 ^ 2 + (Ca) ^ 2625 - 324 = Ca ^ 2<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B301%7D%20" />cosx = ca / hcosx = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B301%7D%20%7D%7B25%7D%20" />B.
Cos x = - 0, 2cosx = ca / h = - 2 / 10 = - 1 / 5ca = - 1h = 5co = ?
Pitágoras 5 ^ 2 = ( - 1) ^ 2 + co ^ 225 - 1 = co2<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B24%7D%20" />calcula tanx = co / ca<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B24%7D%20%7D%7B%20-%201%7D%20" />C.
Tanx = 0.
58tanx = co / ca = 58 / 100 = 29 / 50co = 29ca = 50 h = ?
Pitágorash ^ 2 = 29 ^ 2 + 50 ^ 2h ^ 2 = 841 + 2500h = <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3341%7D%20" />calcula secx = h / ca = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B3341%7D%20%7D%7B50%7D%20" />.