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Aa + bb + cc + dd = d4d, Hallar a + b + c - d?

Aa + bb + cc + dd = d4d, Hallar a + b + c - d.

7Adirfanairam7162

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Andriicer10pchkmu

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Aa + bb + cc + dd = d4d (a * 10 + a) + (b * 10 + b) + (c * 10 + c) + (d * 10 + d) = d * 100 + 40 + d = d * 10 * 10 + 40 + d = d * 10 * (1 + 9) + 40 + d = d * 10 + d * 10 * 9 + 40 + da * 10 + a + b * 10 + b + c * 10 + c + d * 10 + d = d * 10 + d * 10 * 9 + 40 + da * 10 + a + b * 10 + b + c * 10 + c = d * 10 * 9 + 40a * 10 + a + b * 10 + b + c * 10 + c = d * 10 * (1 + 8) + 40a * 10 + a + b * 10 + b + c * 10 + c = d * 10 + d * 10 * 8 + 40a * 10 + a + b * 10 + b + c * 10 + c - d * 10 = d * 10 * 8 + 10 * 410 * (a + b + c - d) + (a + b + c) = 10 * 4 * (d * 2 + 1)10 * (a + b + c - d) = 10 * 4 * (d * 2 + 1) - (a + b + c) a + b + c - d = 4 * (2 * d + 1) - (a + b + c) / 10.