Calcula el numero de moles de un gas que ocupa un volumen de 3 litros, a una temperatura de 20 centigrados y 2, 5 atmofesra de presion.
En resumen
N = moles P x V = n x R x T R = 0. 0821 (atm L / molK) T = 20 + 273 = 293 K n = P x V ```````````` R x T n = 2. 5 atm x 3 L ```````````````````````````` 0. 0821 (atm L / molK) x 293 K n = 0. 3117 moles.
N = moles
P x V = n x R x T
R = 0.
0821 (atm L / molK)
T = 20 + 273 = 293 K
n = P x V ```````````` R x T
n = 2.
5 atm x 3 L ```````````````````````````` 0.
0821 (atm L / molK) x 293 K
n = 0.
3117 moles.
Mira esto si te sive espero que si.
PV = nRT conoces P n R y T despejas V V = (1mol * 0, 082atm * L(mol * K) * 275K) / 2atm V = 11, 275L.
PV = nRT - - > gases ideales P = 740 mmHg - - >0, 97 atm V = 5x10⁻⁵ L (supondre que son litros, no especifico unidades) T = 25°C - > 298, 15 K R = 0, 082 - - > constante de los gases ideales n = numero de moles - - >…