Sen x / 1 + cos x + 1 + cos x / sen x = 2 csc x?
Sen x / 1 + cos x + 1 + cos x / sen x = 2 csc x.
Sen x / 1 + cos x + 1 + cos x / sen x = 2 csc x.
En resumen
<img src="https://tex.z-dn.net/?
Ale051m
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La respuesta es c .
A) COSASENA - (COSA)2 = (SENA)2 COSASENA = (SENA)2 + (COSA)2, COSASENA = 1 RECORDAR SEN2A = 2SENACOSA SEN2A / 2 = SENACOSA SEN2A = 2 A = 15 B) RECODAR : TGA + CTGA = SECACSCA (SECACSCA)2 = SECA + (CSCA)2 , (CSCB)2…
1 simplificar cos α . Sen α . (sen α + csc α ) = recordar cscα = 1 / senx P = cos α . Sen α . (sen α + csc α ) P = cosα. Senα(senα + 1 / senα) P = cosαsenα(sen²α + 1) / senα sen²x = 1 - cos²x ⇒ identidad pitagorica P =…