Rapidoresolver1?
Rapido resolver 1. _ sen(150°) 2. _ cos ( 159°) 3. _"sen 22°30'.
5NLC87264
Rapido resolver 1. _ sen(150°) 2. _ cos ( 159°) 3. _"sen 22°30'.
En resumen
1. - sen(150) = 0. 5 2. - cos(150) = - 0. 86 3. - sen(22)(30) = sen(660) = - 0. 866.
Nenalynda15
1. - sen(150) = 0.
5
2. - cos(150) = - 0.
86
3.
- sen(22)(30) = sen(660) = - 0.
866.