Necesito resolver ( A ∪ B)∩(A∩B³) = A el elevado de b en vez de ser un tres lo sustituyen por una c (a - b)∪(b - a) = (a∪b) - (a∩b) (a∪b)∩b∧c = (a∩b∧c)∪(b∩b∧c).
En resumen
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Heidiamarilis4
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LO MAS PROBABLE ES QUE TEPIDAN HALLAR "AC" A 21 B C Hay una relacion : 4AB = 3BC AB / BC = 3 / 4 constantes a cada uno : AB = 3k y BC = 4k AB = 21 3k = 21 k = 7 ENTONCES BC = 28 Y AC = 7k = 49 SALUDOS.
Holsss! 8 ^ 3 ÷ 4 ^ 3 = 8 aquí el procedimiento : 8 ^ 3 = (8)(8)(8) = 512 4 ^ 3 = (4)(4)(4) = 64 luego : 512 ÷ 64 = 8 saluuudos.
- 81 ^ 3 / 2 ( - 3 ^ 4) 3 / 2 - 3 ^ 6 = - 3 ^ 6 o - 729.
SALUDOS ISABELA.