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An ant crawls at a rate of 216 ft per minute?

An ant crawls at a rate of 216 ft per minute. At this rate, how long does it take the ant to crawl a distance of 515 ft? Enter your answer as a mixed number in simplest form in the box.

2Majitof05p5lyju

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Hi, I don't have a good use ofEnglish so excuse me if Icommit grammatical errors. Ant Crawling Rate = <img src="https://tex.z-dn.net/?

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Nayudernaale

7

Hi,

I don't have a good use ofEnglish so excuse me if Icommit grammatical errors.

Ant Crawling Rate = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B216ft%7D%7Bm%7D%20" />

Then you use the Speed equation to get the time that takes the ant to crawl the distance of 515ft

<img src="https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20" />

v = speed

d = distance travelled

t = time taken

Just replace data :

<img src="https://tex.z-dn.net/?f=%20%28%5Cfrac%7B216ft%7D%7Bm%7D%29%20%3D%20%5Cfrac%7B515ft%7D%7Bt%7D%20" />

<img src="https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B515ft%7D%7B%20%5Cfrac%7B216ft%7D%7Bm%7D%20%7D%20" />

<img src="https://tex.z-dn.net/?f=t%3D%20%28%5Cfrac%7B515%7D%7B216%7D%20%29m" />

<img src="https://tex.z-dn.net/?f=t%3D2.38minutes" />

This number expressed as a mixed number is :

<img src="https://tex.z-dn.net/?f=2.38%3D%20%5Cfrac%7B515%7D%7B216%7D%3D2%20%5Cfrac%7B83%7D%7B216%7D%20%20" />

Hope that I helped you.

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Respuesta 2

Florapazatp07l7u

4

216 ft⇒ 1 minute

515 ft⇒ A minutes

A = 515 * 1 / 216

A = 515 / 216

515 / 216 = (432 / 216) + (83 / 216) = 2 + (83 / 216)

Answer :

2 83 / 216 minutes.