4 log (x + 1) = log 625 ayudenme a resolver est ejersisio?
4 log (x + 1) = log 625 ayudenme a resolver est ejersisio.
4 log (x + 1) = log 625 ayudenme a resolver est ejersisio.
En resumen
4 log (x + 1) = log 625 Propiedades : n log A = log Aⁿ log A + log B = log (A· B) log A - log B = log (A / B) Por lo tanto : log625 = log5⁴ = 4 log 5 Luego : 4 log(x + 1) = 4 log 5 log(x + 1) = log 5 10ˣ⁺¹ = 10⁵ x + 1 = 5 x = 5 - 1 x = 4.
Rociogamer
4 log
(x + 1) = log 625
Propiedades : n log A = log Aⁿ
log A + log B = log (A· B)
log A - log B = log (A / B)
Por lo tanto : log625 = log5⁴ = 4
log 5
Luego : 4 log(x + 1) = 4 log 5 log(x + 1) = log 5 10ˣ⁺¹ = 10⁵ x + 1 = 5 x = 5 - 1
x = 4.
Sólo pones exactamente eso en tu calculadora y da : 2. 230291677x10 a la - 4.
Log2x = log10 log2x = log10 2x = 10 x = 5 ∨.
Log(ab) = log a + log b = 3 + 4 = 7 log a / b = log a - log b = 3 - 4 = - 1 log a ^ 2 = 2 log a = 2 (3) = 6 log ab este es igual a primero Suerte pd : El punto uno es asi log(a * b) o que quieres decir con log(a' * b).
Veamos : del dato, x >0 Log (x - 1) + Log x = Log 10 Log (x - 1)(x) = Log 10 x(x - 1) = 10 x² - x - 10 = 0 x = 1 + - √1² - 4 * 1 * ( - 10) / 2 * 1 x = 1 + - √41 / 2 x₁ = 1 + √41 / 2≈ 3. 7.
Log (x + 6) - ½ log (2x - 3) = 2 - log 25 Log(x + 6) - log((2x - 3) ^ 1 / 2)) = log (1 / 5) - log25 log ((x + 6) / ((2x - 3) ^ 1 / 2))) = log ((1 / 5) / 25) ((x + 6) / ((2x - 3) ^ 1 / 2))) = ((1 / 5) / 25) (x + 6) / (1,…
5 - log(x² + 4) - log(x - 2) = 3 + log(x - 2) 2 - log(x² + 4) = 2log(x - 2) 2 - log(x² + 4) = log (x - 2)² 2 - log(x² + 4) = log(x² - 4x + 4) 2 = log(x² - 4x + 4) + log(x² + 4) 2 = log[(x² - 4x + 4)(x² + 4)] log10² =…