Ayudenme a resolver estos logaritmos por favorlog x + log 2 = 1log x + log (10x) = 3?
Ayudenme a resolver estos logaritmos por favor log x + log 2 = 1 log x + log (10x) = 3.
Ayudenme a resolver estos logaritmos por favor log x + log 2 = 1 log x + log (10x) = 3.
En resumen
Log2x = log10 log2x = log10 2x = 10 x = 5 <img src="https://tex.z-dn.net/?f=logx%2Blog%2810x%29%3D3" /> <img src="https://tex.z-dn.net/?f=log%2810%20x%5E%7B2%7D%20%29%3Dlog1000" /> <img src="https://tex.z-dn.net/?f=%2010x%5E%7B2%7D%20%3D1000" /> <img src="https://tex.z-dn.net/?
Log2x = log10
log2x = log10
2x = 10
x = 5
<img src="https://tex.z-dn.net/?f=logx%2Blog%2810x%29%3D3" />
<img src="https://tex.z-dn.net/?f=log%2810%20x%5E%7B2%7D%20%29%3Dlog1000" />
<img src="https://tex.z-dn.net/?f=%2010x%5E%7B2%7D%20%3D1000" />
<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%3D100" />
<img src="https://tex.z-dn.net/?f=x%3D10" />∨<img src="https://tex.z-dn.net/?f=x%3D-10" />.
Log(ab) = log a + log b = 3 + 4 = 7 log a / b = log a - log b = 3 - 4 = - 1 log a ^ 2 = 2 log a = 2 (3) = 6 log ab este es igual a primero Suerte pd : El punto uno es asi log(a * b) o que quieres decir con log(a' * b).
3[log(x) + 2 / 5 log(y) - log(z)] es 1 3 / 4 log(x) - log(y) + 1 / 2 log (z)es2.
4 log (x + 1) = log 625 Propiedades : n log A = log Aⁿ log A + log B = log (A· B) log A - log B = log (A / B) Por lo tanto : log625 = log5⁴ = 4 log 5 Luego : 4 log(x + 1) = 4 log 5 log(x + 1) = log 5 10ˣ⁺¹ = 10⁵ x + 1 =…
Veamos : del dato, x >0 Log (x - 1) + Log x = Log 10 Log (x - 1)(x) = Log 10 x(x - 1) = 10 x² - x - 10 = 0 x = 1 + - √1² - 4 * 1 * ( - 10) / 2 * 1 x = 1 + - √41 / 2 x₁ = 1 + √41 / 2≈ 3. 7.
Log (x + 6) - ½ log (2x - 3) = 2 - log 25 Log(x + 6) - log((2x - 3) ^ 1 / 2)) = log (1 / 5) - log25 log ((x + 6) / ((2x - 3) ^ 1 / 2))) = log ((1 / 5) / 25) ((x + 6) / ((2x - 3) ^ 1 / 2))) = ((1 / 5) / 25) (x + 6) / (1,…