La masa molecular de una sustancia es 180, 7g / mol y su composición centesimal es ; C = 26, 68% H = 2, 24% O = 71, 08% halla su fórmula empírica y molecular (Datos C = 12, 01 H = 1 ; O = 16)?

C = 26.

68 g / 12 g / mol = 2.

223 mol

H = 2.

24 g / 1 g / mol = 2.

24 mol

O = 71.

08 g / 16 g / mol = 4.

443 mol

dividir cada elemento entre el menor de los resultados

C = 2.

223 mol / 2.

223 mol = 1

H = 2.

24 mol / 2.

223 mol = 1

O = 4.

443 mol / 2.

223 mol = 2

FORMULA EMPIRICA = C₁H₁O₂

MASA MOLECULAR DE LA FE

C = 1 x 12 = 12 g / mol

H = 1 x 1 = 1 g / mol

O = 2 x 16 = 32 g / mol

```````````````````````````````````` Mm = 45 g / mol

n = 180.

7 g / mol `````````````````` = 4 45 g / mol

formula molecular = (FE)n

FM = (C₁H₁O₂)₄ = C₄H₄O₈.