¿cuál será el volumen que ocupara 2g de oxígeno molecular a 20C y 728Torr?
¿cuál será el volumen que ocupara 2g de oxígeno molecular a 20C y 728Torr?
En resumen
P x V = n x R x T Moles (n) = 2 g / 32 g / mol n = 0. 0625 mol T = 20 ºC + 273 = 293 K R = 0. 0821 ( L x atm) / (mol x K) P = 728 Torr = 0. 958 atm. V = n x R xT ```````````` P V = 0. 0625 mol x 293 K x 0.
Mejor respuesta
10
P x V = n x
R x T
Moles (n) = 2 g / 32 g / mol
n = 0.
0625 mol
T = 20 ºC + 273 = 293 K
R =
0.
0821 ( L x atm) / (mol x K)
P = 728
Torr = 0.
958 atm.
V = n x R xT ```````````` P
V = 0.
0625 mol x 293 K x 0.
0821 ( L x atm) / (mol x K) ```````````````````````````````````````````````````````````````````````` 0.
958 atm
V = 1.
56 LITROS.