Calcular la composicion porcentual de Al(oH)3?
Calcular la composicion porcentual de Al(oH)3.
Calcular la composicion porcentual de Al(oH)3.
CALCULAR MASA MOLECULAR
Al = 1 x 27 = 27 g / mol
O = 3 x 16 = 48 g / mol
H = 3 x 1 = 3 g / mol
`````````````````````````````````` Mm = 78 g / mol
Aluminio
78 g - - - - - 100 %
27 g - - - - - x
x = 34, 31 %
oxigeno
78 g - - - - - 100 %
48 g - - - - - x
x = 61, 53 %
hidrógeno
78 g - - - - - 100 % 3 g - - - - - x
x = 3.
85 %.
Calcular masa moleculares del Al2(SO4)3 Al : 2 x 26. 98 = 53. 96 g / mol S : 3 x 32. 06 = 96. 18 g / mol O : 12 x 16 = 192 g / mol `````````````````````````````````````` Mm = 342. 14 g / mol Aluminio : 342. 14 g - - - -…
Ca3(PO4)2 * 5H2O calcular MmCa : 3 x 40 = 120 g / mol P : 2 x 31 = 62 g / mol O : 13 x 16 = 208 g / mol H : 10 x 1 = 10 g / mol```````````````````````````````````````````````````````` Mm = 400 g / mol% calcio 400 g - -…
Respuesta : %C = 92, 31 y %H = 7, 69Explicación : Carbono masa atómica 12 * 6 = 72, Hidrogeno , masa atomica 1 * 6 = 6, total masa Benceno 78, % Hidrogeno = 6 / 78 * 100 = 7, 69 y % Carbono = 72 / 78 * 100 = 92, 31%.