Ayudaaaaaa por favor?
Ayudaaaaaa por favor! Calcular la molaridad de una disolución de HNO3 al 36. 7% y d = 1. 225g / ml.
Pregunta de Química · 1 respuesta · 3 votos · mejor respuesta de Natanbonates9429
En resumen
Mm HNO3 = 63 g / mol M = 1. 225 g x 1000 mL x 36. 7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3 M = 7. 136 molar.
Respuestas de la comunidad
Mejor respuesta
Mm HNO3 = 63 g / mol
M = 1.
225 g x 1000 mL x 36.
7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3
M = 7.
136 molar.
Preguntas frecuentes
Ayudaaaaaa por favor?
Mm HNO3 = 63 g / mol M = 1. 225 g x 1000 mL x 36. 7 g disolución x 1 mol HNO3 ```````````` ````````````` ```````````````````````` `````````````````` 1 mL 1 L 100 g disolución 63 g HNO3 M = 7.