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En resumen
M Zn = 100 gMmZn = 65 g / molV = 100 g Zn x 1 mol Zn x 22, 4 L H2 `````````````````` `````````````````````` 65 g Zn 1 mol ZnV = 34. 46 L```````````````````````````````````````````````````````````````````````````````````````````````````````````````CN T = 273 K P = 1 atm R = 0.
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M Zn = 100 gMmZn = 65 g / molV = 100 g Zn x 1 mol Zn x 22, 4 L H2 `````````````````` `````````````````````` 65 g Zn 1 mol ZnV = 34.
46 L```````````````````````````````````````````````````````````````````````````````````````````````````````````````CN T = 273 K P = 1 atm R = 0.
0821 (L atm / mol K)Ley de los gases idealesV x P = n x R x Tcalcular moles de Znn = masa / Mmn = 100 g / 65 g / moln = 1.
538 molescalcular VolumenV = (1.
538 mol x 0.
0821 (L atm / mol K) x 273 K ) / 1 atmV = 34.
46 L.
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