The width of a rectangular field is 60% of its length?
The width of a rectangular field is 60% of its length. How big is the field, if the owner occupied 280 meters of cyclonic fence to fence it?
En resumen
First : 60% = 60 / 100 = 0. 6 If the width is 60% of this length : x = 0. 6y ec. 1 2x + 2y = 280 ec. 2 replacing ec. 1 on ec. 2 : 2 * (0. 6y) + 2y = 280 1. 2y + 2y = 280 3. 2y = 280 y = 280 / 3. 2 y = 87. 5 The length is 87. 5m On the ec. 1 : x = 0. 6y x = 0.
Mejor respuesta
First : 60% = 60 / 100 = 0.
6
If the width is 60% of this length :
x = 0.
6y ec.
1
2x + 2y = 280 ec.
2
replacing ec.
1 on ec.
2 :
2 * (0.
6y) + 2y = 280
1.
2y + 2y = 280
3.
2y = 280
y = 280 / 3.
2
y = 87.
5
The length is 87.
5m
On the ec.
1 :
x = 0.
6y
x = 0.
6 * 87.
5
x = 52.
5
The width is 52.
5m
Now the area of the field is :
A = L * W
A = 87.
5 * 52.
5
A = 4593.
75
The field area is 4593.
75 m²
Saludos.
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