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T ala 2 - 8 = 1 / 3t ala 2 - 2?

T ala 2 - 8 = 1 / 3t ala 2 - 2.

2Leidisitaa

En resumen

X² - 8 = (1 / 3)x² - 2 1 - (1 / 3) = 2 / 3→x² - (x² / 3) = 2x² / 3 x² - 8 = (x² / 3) - 2 x² - (x² / 3) - 8 = - 2 (2x² / 3) - 8 + 2 = 0 (2x² / 3) - 6 = 0 6x = 9→x = 9 / 6→3 / 2 2x² / 3 = 6 3 / 2(2 / 3)x² = 6(3 / 2) →3 / 2(2 / 3) = 1 →6(3 / 2) = 9 x² = 9 x = + - √9 x = 3 o x = - 3.

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Federixto0823

1

X² - 8 = (1 / 3)x² - 2 1 - (1 / 3) = 2 / 3→x² - (x² / 3) = 2x² / 3

x² - 8 = (x² / 3) - 2

x² - (x² / 3) - 8 = - 2

(2x² / 3) - 8 + 2 = 0

(2x² / 3) - 6 = 0 6x = 9→x = 9 / 6→3 / 2

2x² / 3 = 6

3 / 2(2 / 3)x² = 6(3 / 2) →3 / 2(2 / 3) = 1 →6(3 / 2) = 9

x² = 9

x = + - √9

x = 3 o x = - 3.