MatemáticasBásico1 respuestas

Solucionar las ecuaciones log3(x + 2) = 2log5(x + 3) = 4?

Solucionar las ecuaciones log3(x + 2) = 2 log5(x + 3) = 4.

Calculadora interactiva

ax² + bx + c = 0

En resumen

Log3(x + 2) = 2 0. 4(x + 2) = 2 0. 4x + 0. 8 = 2 0. 4x = 2 - 0. 8 0. 4x = 1. 2 X = 1. 2 / 0. 4 X = 3 La otra es : log5(x + 3) = 4 0. 6x + 1. 8 = 4 0. 6x = 4 - 1. 8 0. 6x = 2. 2 X = 2. 2 / 0. 6 X = 3. 6 = = 11 / 3.

Mejor respuesta

Magda28
3

Log3(x + 2) = 2

0.

4(x + 2) = 2

0.

4x + 0.

8 = 2

0.

4x = 2 - 0.

8

0. 4x = 1.

2

X = 1.

2 / 0.

4

X = 3

La otra es :

log5(x + 3) = 4

0.

6x + 1.

8 = 4

0.

6x = 4 - 1.

8

0. 6x = 2.

2

X = 2.

2 / 0.

6

X = 3.

6 = = 11 / 3.