Log3(x + 4) + Log3(x - 2) = 3?

Asumo que 3 es la base

<img src="https://tex.z-dn.net/?f=%5C%5C%5Clog_3%28x%2B4%29%2B%5Clog_3%28x-2%29%3D3%5C%5C%20D%3A%20x%3E2%5C%5C%20%5Clog_3%28x%2B4%29%28x-2%29%3D3%5C%5C%203%5E3%3D%28x%2B4%29%28x-2%29%5C%5C%2027%3Dx%5E2-2x%2B4x-8%5C%5C%2027%3Dx%5E2%2B2x-8%5C%5C%20x%5E2%2B2x-35%3D0%5C%5C%20x%5E2%2B7x-5x-35%3D0%5C%5C%20x%28x%2B7%29-5%28x%2B7%29%3D0%5C%5C%20%28x-5%29%28x%2B7%29%3D0%5C%5C%20x%3D5%20%5Cvee%20x%3D-7%5C%5C%20-7%5Cnot%20%5Cin%20D%5C%5C%20%5Cunderline%7Bx%3D5%7D%20" />2 \ \ \ log_3(x + 4)(x - 2) = 3 \ \ 3 ^ 3 = (x + 4)(x - 2) \ \ 27 = x ^ 2 - 2x + 4x - 8 \ \ 27 = x ^ 2 + 2x - 8 \ \ x ^ 2 + 2x - 35 = 0 \ \ x ^ 2 + 7x - 5x - 35 = 0 \ \ x(x + 7) - 5(x + 7) = 0 \ \ (x - 5)(x + 7) = 0 \ \ x = 5 \ vee x = - 7 \ \ - 7 \ not \ in D \ \ \ underline{x = 5} " alt = " \ \ \ log_3(x + 4) + \ log_3(x - 2) = 3 \ \ D : x>2 \ \ \ log_3(x + 4)(x - 2) = 3 \ \ 3 ^ 3 = (x + 4)(x - 2) \ \ 27 = x ^ 2 - 2x + 4x - 8 \ \ 27 = x ^ 2 + 2x - 8 \ \ x ^ 2 + 2x - 35 = 0 \ \ x ^ 2 + 7x - 5x - 35 = 0 \ \ x(x + 7) - 5(x + 7) = 0 \ \ (x - 5)(x + 7) = 0 \ \ x = 5 \ vee x = - 7 \ \ - 7 \ not \ in D \ \ \ underline{x = 5} " align = "absmiddle" class = "latex - formula">.