Hallar a + b + c + d si : aa + bb + cc = abc?
Hallar a + b + c + d si : aa + bb + cc = abc.
Hallar a + b + c + d si : aa + bb + cc = abc.
Descomponiendo y undato que a , b y c son menores que 10 : = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = aa + bb + cc = abc
10a + a + 10b + b + 10c + c = 100a + 10b + 10c 11a + 11b + 11c = 100a + 10b + c 11b - 10b + 11c - c = 100a - 11a b + 10c = 89a ←Probando valores : 9 + 10(8) = 89(1) ←Los valores son :
→b = 9, c = 8 , a = 1
Respuesta : = = = = = = = = = = =
a + b + c = 1 + 9 + 8 = 18.
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Abc + cbc = 495 abc + c b c 495 c + c = 2c = 5? IMPOSIBLE Si el número de las unidades es iguaal en los dos sumandos, su suma debe ser par.
Hola, Descomponiendo canonicamente : (100a + 10b + c) - (100c + 10b + a) = 792 99a - 99c = 792 99(a - c) = 792 a - c = 8 Como c 0 , por que es primera cifra : c = 1 - - - > a = 9 Por tanto : a + c = 10.