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Edusanmartin819
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F(x) = 3X + 2 ; g(x) = (X + 3) / (2X + 1)

g o f = g[f(x)]

g[f(x)] = [(3X + 2) + 3] / [2(3X + 2) + 1]

g[f(x)] = [3X + 5] / [6X + 4 + 1]

g[f(x)] = [3X + 5] / [6X + 5]

f o g : f[g(x)] f[g(x)] = 3[(X + 3) / (2X + 1)] + 2

3[(X + 3) / (2X + 1)] = [(3X + 9) / (2X + 1)] + 2

[(3X + 9) / (2X + 1)] + 2 / 1 = [(3X + 9) + 2(2X + 1)] / [2X + 1]

[(3X + 9) + (4X + 2)] / [2X + 1]

[3X + 9 + 4X + 2] / [2X + 1]

[7X + 11] / [2X + 1]

f[g(x)] = [7X + 11] / [2X + 1].