Exprese como un logaritmo = 1 / 3 log a(x2 - 1) - log aY - 4logaZ?
Exprese como un logaritmo = 1 / 3 log a(x2 - 1) - log aY - 4logaZ.
Exprese como un logaritmo = 1 / 3 log a(x2 - 1) - log aY - 4logaZ.
En resumen
Logarithmic Functions y = logax x = a y (exponential form) Properties of Logarithms 1. Loga1 = 0 because a0 = 1 2. Logaa = 1 because a1 = a 3. Logaa x = x and = x Inverse Property 4.
4469699
Logarithmic Functions
y = logax x = a
y
(exponential form)
Properties of Logarithms
1.
Loga1 = 0 because a0 = 1
2.
Logaa = 1 because a1 = a
3.
Logaa
x = x and = x Inverse Property
4.
If logax = logay then x = y One - to - one
Natural Logarithms
y = lnx if x = e
y
Properties of Logarithms
1.
Ln1 = 0 because e0 = 1
2.
Lne = 1 because e1 = e
3.
Lnex = x and elnx = x inverse properties
4.
If lnx = lny then x = y one - to - one
Logarithmic Properties
1.
Product—loga(xy) = logax + logay
2.
Quotient—loga(x / y) = logax - logay
3.
Power—logax
y = ylogax
Natural Logarithmic Properties
1.
Product—ln(xy) = lnx + lny
2.
Quotient—ln(x / y) = lnx - lny
3.
Power—lnxy = ylnx
Change of Base
Base b
logax = logbx
logba
Base 10
logax = log10x
log10a
Base e
Logax = lnx
lna.
Por teoría : log a - log b = log a / b En tu ejemplo : log (2a² + 5a + 3) - log (2a - 3) + 2 = log [(2a² + 5a + 3) / (2a - 3)] + 2.
Aquí les dejo los ejercicios de la A hasta la F.