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Dada la funcion f(x){x2 - 2x + 1 x ≥3 g(x) √x - 1 x≥1 |x - 5| x?

Dada la funcion f(x){x2 - 2x + 1 x ≥3 g(x) √x - 1 x≥1 |x - 5| x.

En resumen

A) (f + g)(0) (f + g)(0) = f(0) + g(0) (f + g)(0) = |0 - 5| + (f + g)(0) = 5 + 2 / 3 b) (f o g)(5) g(5) = √5 - 1 = √4 = √ f(2) = 2 – 5 = 3 (f o g)(5) = 3.

Mejor respuesta

2

A) (f + g)(0)

(f + g)(0) = f(0) + g(0)

(f + g)(0) = |0 - 5| + (f + g)(0) = 5 + 2 / 3

b) (f o g)(5) g(5) = √5 - 1 = √4 = √ f(2) = 2 – 5 = 3 (f o g)(5) = 3.