Dada la funcion f(x){x2 - 2x + 1 x ≥3 g(x) √x - 1 x≥1 |x - 5| x?
Dada la funcion f(x){x2 - 2x + 1 x ≥3 g(x) √x - 1 x≥1 |x - 5| x.
Dada la funcion f(x){x2 - 2x + 1 x ≥3 g(x) √x - 1 x≥1 |x - 5| x.
En resumen
A) (f + g)(0) (f + g)(0) = f(0) + g(0) (f + g)(0) = |0 - 5| + (f + g)(0) = 5 + 2 / 3 b) (f o g)(5) g(5) = √5 - 1 = √4 = √ f(2) = 2 – 5 = 3 (f o g)(5) = 3.
A) (f + g)(0)
(f + g)(0) = f(0) + g(0)
(f + g)(0) = |0 - 5| + (f + g)(0) = 5 + 2 / 3
b) (f o g)(5) g(5) = √5 - 1 = √4 = √ f(2) = 2 – 5 = 3 (f o g)(5) = 3.