(ctgθ + cscθ)²≡ 1 + cos÷ 1 - cosθ?
(ctgθ + cscθ)²≡ 1 + cos÷ 1 - cosθ.
(ctgθ + cscθ)²≡ 1 + cos÷ 1 - cosθ.
En resumen
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Demostrar. CscФ cosФ - - - - - - - - + - - - - - - - - - - - = 2cotФ Pero cscФ = 1 / senФ , secФ = 1 / cosФ y secФ senФ cosФ / senФ = cotФ reemplazas 1 - - - - - - - - senФ - - - - - - - - - - - - + cotФ = 2cotФ Aplicas…
Respuesta : es 88Explicación paso a paso : usamos el cuadrante 2ponemos los valos - x = - 3 y = 1buscamos el triangulo mas cerca al angulo y tambien el radio con pitagorasbuscamos ctgθ = - 3 / 1 cosec²θ = 100 / 1 3tgθ =…