¿Cómo se podrían repartir 2310 € entre tres hermanos de forma que al mayor le corres - ponda la mitad que al menor, y a este, el triple que al mediano?

Respuesta : Al mayor le corresponden 630€Al mediano de corresponden 420€Al menor le corresponden 1260€Explicación paso a paso : sean : x - - > el hermano mayory - - > el hermano medianoz - - > el hermano menor = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = - Armo el sistema de ecuaciones - A los tres hermanos les corresponden 2310x + y + z = 2310 (1)

Al mayor le corresponde la mitad que al menorx = z / 2 (2)

A este (el menor) le corresponde el triple que al medianoz = 3y (3) = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = despejar y de (3)z / 3 = y (4)reemplazar (4) y (2) en (1)z / 2 + z / 3 + z = 2310

despejar z(3z + 2z) / 6 + z = 23105z + 6z = 2310 * (6)11z = 13860z = 13860 / 11 = 1260

reemplazar z en (2)x = 1260 / 2x = 630

reemplazar z en (4)1260 / 3 = yy = 420

Reemplazar x, y, z en (1) para verificar630 + 420 + 1260 = 23102310 = 2310.