Como puedo hallar la base mayor de un trapecio sabiendo que la base menor es 10cm , la altura es 8cm y su area es 112.
En resumen
Area = (base mayor + base menor) * h / 2 reemplazando datos 112 = (base mayor + 10) * 8 / 2 112 = (base mayor + 10) * 4 112 / 4 = base mayor + 10 28 = base mayor + 10 base mayor = 28 - 10 base mayor = 18.
Josepa16
Area = (base mayor + base menor) * h / 2
reemplazando datos
112 = (base mayor + 10) * 8 / 2
112 = (base mayor + 10) * 4
112 / 4 = base mayor + 10
28 = base mayor + 10
base mayor = 28 - 10
base mayor = 18.
Area del trapecio = base mayor mas base menor por altura dividida en dos AT = B + b * H / 2 A = (80 + 120)cm * 60cm / 2 = 6. 000cm2.
Area del trapecio : (B×b / 2)×h = 24 base mayor : B = 3b = 3(2) = 6 base menor : b = 2 altura : 4 (3b×b / 2)×4 3b²×2 = 24 3b² = 12 b² = 4 b = 2.
A = B + b * h / 2a = 14 + 8 * 5 / 2a = 55m².
20² + 6² = x²2√109 = xespero que te ayude.