Ayudenme a resolvera) 3x ^ 2 + 5x = 0b) 2x - 4 = 0c) 2x - 3 + 1 = 0d) 9x - 3x - 2 = 0e) 2x ^ 2 + 3x + 1 = 0?
Ayudenme a resolver a) 3x ^ 2 + 5x = 0 b) 2x - 4 = 0 c) 2x - 3 + 1 = 0 d) 9x - 3x - 2 = 0 e) 2x ^ 2 + 3x + 1 = 0.
Ayudenme a resolver a) 3x ^ 2 + 5x = 0 b) 2x - 4 = 0 c) 2x - 3 + 1 = 0 d) 9x - 3x - 2 = 0 e) 2x ^ 2 + 3x + 1 = 0.
En resumen
A). 3x² + 5x = 0 8x³b). 2x - 4 = 0 2x = 0 + 4 x = 4 / 2 x = 2c). 2x - 3 + 1 = 0 2x = 0 + 3 - 1 2x = 2 x = 2 / 2 x = 1d). 9x - 3x - 2 = 0 6x = 0 + 2 6 / 2 = x 3 = x.
A). 3x² + 5x = 0 8x³b).
2x - 4 = 0 2x = 0 + 4 x = 4 / 2 x = 2c).
2x - 3 + 1 = 0 2x = 0 + 3 - 1 2x = 2 x = 2 / 2 x = 1d).
9x - 3x - 2 = 0 6x = 0 + 2 6 / 2 = x 3 = x.
4x3 x>9 xE(9, + inf).
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En la primera hay→ 3 palitos En la segunda hay→ 5 palitos En la tercera hay→ 7 palitos Y así sucesivamente 3, 5, 7, . Razón = 2 tn = 2n + 1 t39 = 2(39) + 1 = 79 3, 5, 7, . , 79 Suma de todos los palitos = (3 + 79)39 / 2…
(x - 4) (x - 12) (x² + 12x)( - 4x + 48) x² = 12x - 4x + 48x² = 48÷8 x² = 6x = √6x = 2.