Ayuda?
Ayuda! Log x = 1 + log√ x log₂ (x - 3) - log₂ (2x + 1) = - log₂4 log₃(9x - 5) = log₃ (5x - 7) log x² + log x³ + log x⁴ - log x⁶ = log 16 3 log₂ x - 2 log₄ x = 2.
9Lflme
En resumen
1) logx - 1 / 2 × logx ^ (1 / 2) = 1 logx ^ (1 / 2) = 1 1 / 2 × logx = 1 logx = 2 10 ^ 2 = x x = 100 2)log(x - 3) / (2x + 1) = log(1 / 4) (x - 3 ) / (2x + 1) = 1 / 4 4x - 12 = 2x + 1 2x = 13 x = 13 / 2 3)x = - 1 / 2 4) × = 2 ^ (4 / 3) 5) x = 2.
Mejor respuesta
Gabrielys05
1) logx - 1 / 2 × logx ^ (1 / 2) = 1
logx ^ (1 / 2) = 1
1 / 2 × logx = 1
logx = 2
10 ^ 2 = x
x = 100
2)log(x - 3) / (2x + 1) = log(1 / 4)
(x - 3 ) / (2x + 1) = 1 / 4
4x - 12 = 2x + 1
2x = 13
x = 13 / 2
3)x = - 1 / 2
4) × = 2 ^ (4 / 3)
5) x = 2.