A1. Hallar el valor de “m + n”, en la ecuación : x³ + mx² + nx + 7 = 0 , si 1 - 2√2 es una de sus raíces (m, n son racionales). (A) - 8 (B) - 3 (C) - 5 (D) - 7 (E) Ninguno.
ax² + bx + c = 0
En resumen
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10x² - 11x + 3 = 0 hallando factores , obtenemos dos raices 5x - 3 2x - 1 5x - 3 = 0 x1 = 3 / 5 2x - 1 = 0 x2 = 1 / 2 la menor raiz es 1 / 2 6x² - 7x + k = 0 se obtienen dos factores 3x - 1 / 2 2x - 2 3x - 1 / 2 = 0 x1…
Si se puede pero no siempre como por ejemplo : raiz exacta de 13 no hay, en cambio la raiz de 16 es 4 porque 4 * 4 es igual a 16.
Hola! Para hallar el valor de la constante y que la función a su vez tenga esa raíz ya definida solo tienes que sustituir el valor de la raíz en la ecuación, esto es : que al insertar x = 2 resulta 4p - 2 + 5 - 3p = 0 "…