2x - 5y = 134y + z = - 8x - y - z = - 2?
2x - 5y = 13 4y + z = - 8 x - y - z = - 2.
2x - 5y = 13 4y + z = - 8 x - y - z = - 2.
En resumen
Despejando "x" : <img src="https://tex.z-dn.net/?f=2x%20-%205y%3D13%0A" /> <img src="https://tex.z-dn.net/?f=2x%3D%2013%2B5y" /> <img src="https://tex.z-dn.net/?f=x%3D%20%2813%2B5y%29%2F2" /> Despejando "z" : <img src="https://tex.z-dn.net/?
Despejando "x" :
<img src="https://tex.z-dn.net/?f=2x%20-%205y%3D13%0A" />
<img src="https://tex.z-dn.net/?f=2x%3D%2013%2B5y" />
<img src="https://tex.z-dn.net/?f=x%3D%20%2813%2B5y%29%2F2" />
Despejando "z" :
<img src="https://tex.z-dn.net/?f=4y%2Bz%3D-8" />
<img src="https://tex.z-dn.net/?f=z%3D%20-8-4y" />
Entonces, hallamos el valor de "y" :
<img src="https://tex.z-dn.net/?f=x-y-z%3D%20-2" />
<img src="https://tex.z-dn.net/?f=%5B%2813%2B5y%29%2F2%5D-y-%28-8-4y%29%3D-2" />
<img src="https://tex.z-dn.net/?f=%5B%2813%2B5y%29%2F2%5D-y-%2B8%2B4y%3D-2" />
<img src="https://tex.z-dn.net/?f=%5B%2813%2B5y%29%2F2%5D%2B8%2B3y%3D-2" />
<img src="https://tex.z-dn.net/?f=%2813%2B5y%2B16%2B6y%29%20%2F%202%20%3D-2" />
[img = 10]
[img = 11]
[img = 12]
Obteniendo el valor de "x" :
[img = 13]
[img = 14]
[img = 15]
[img = 16]
Obteniendo elvalor de "z" :
[img = 17]
[img = 18]
[img = 19]
Rpta :
x = - 1
y = - 3
z = 4.
2. 6 si esto te ayuda.
Recordemos que el rombo se caracteriza por tener la lados iguales y sus diagonales se cortan en partes iguales y perpendicularmente (90°) ademas que tienen los angulo opuestos iguales asi que al cortase las diagonales…