2(x + 3) (x + 2) + 5 = (x + 3)(x + 1) + 6 me piden desarrollo?
2(x + 3) (x + 2) + 5 = (x + 3)(x + 1) + 6 me piden desarrollo.
2(x + 3) (x + 2) + 5 = (x + 3)(x + 1) + 6 me piden desarrollo.
En resumen
2(x + 3)(x + 2) + 5 = (x + 3)(x + 1) + 6 (2x + 6)(x + 2) + 5 = x ^ 2 + x + 3x + 3 + 6 2x ^ 2 + 4x + 6x + 12 + 6 = x ^ 2 + 4x + 9 2x ^ 2 + 10x + 18 = x ^ 2 + 4x + 9 2x ^ 2 - x ^ 2 + 10x - 4x + 18 - 9 = 0 x ^ 2 + 6x + 9 = 0 (x + 3)(x + 3) = 0 x1 = - 3 x2 = - 3.
2(x + 3)(x + 2) + 5 = (x + 3)(x + 1) + 6
(2x + 6)(x + 2) + 5 = x ^ 2 + x + 3x + 3 + 6
2x ^ 2 + 4x + 6x + 12 + 6 = x ^ 2 + 4x + 9
2x ^ 2 + 10x + 18 = x ^ 2 + 4x + 9
2x ^ 2 - x ^ 2 + 10x - 4x + 18 - 9 = 0
x ^ 2 + 6x + 9 = 0
(x + 3)(x + 3) = 0
x1 = - 3
x2 = - 3.
Ahi te va la solución.
Resolver. X(x + 2) + 5 = 4 x² + 2x + 5 = 4 x² + 2x + 5 - 4 = 0 x² + 2x + 1 = 0 Factorizas trinomio al cuadrado perfecto (x + 1)² = 0 Tiene como solución 2 raices identicas (x + 1)(x + 1) = 0 x + 1 = 0 x = - 1 Solución.…