1. si k3 + 10 = 74, halle la suma de 4k2 + 1 =?
1. si k3 + 10 = 74, halle la suma de 4k2 + 1 =.
1. si k3 + 10 = 74, halle la suma de 4k2 + 1 =.
En resumen
K³ + 10 = 74 k³ = 64 k = 4 4k² + 1 = 4(4²) + 1 = 4(16) + 1 = 64 + 1 = 65 Por tanto 4k² + 1 = 65.
K³ + 10 = 74
k³ = 64
k = 4
4k² + 1 = 4(4²) + 1 = 4(16) + 1 = 64 + 1 = 65
Por tanto 4k² + 1 = 65.
25 = 5, 1, 25 30 = 1, 2, 3, 5, 6, 10, 15, 30 64 = 1, 2, 4, 8, 16, 32, 64 100 = 1, 2, 4, 5, 10, 20, 25, 50, 100 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 40 = 1, 2, 4, 5, 8, 10, 20, 40 90 = 1, 2, 3, 5, 6, 9, 10, 15,…
La suma de los angulos interiores de un pentagono es 540°.
X / y + y / x = 26 / 5 si el numero es entero y = 1 x / 1 + 1 / x = 26 / 5 (x * x + 1 * 1) / x = 26 / 5 (x² + 1) / x = 26 / 5.