Si se cuenta con 980g?
Si se cuenta con 980g. De fecl3 para realizar la sgte operacion quimica : fecl3 + NaOH - - - - - - - - - - fe(oh)3 + Nacl¿Cuantos gramos de fe(oh)3 se produciran?
Si se cuenta con 980g. De fecl3 para realizar la sgte operacion quimica : fecl3 + NaOH - - - - - - - - - - fe(oh)3 + Nacl¿Cuantos gramos de fe(oh)3 se produciran?
En resumen
FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl Mm FeCl3 = 162. 20 g / mol Fe(OH)3 = 106. 86 g / mol g Fe(OH)3 = 980 g FeCl3 x 1 mol FeCl3 x 1 mol Fe(OH)3 x 106. 86 gFe(OH)3 ```````````````````````` ````````````````````````````` ``````````````````````````````` 162.
FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
Mm FeCl3 = 162.
20 g / mol Fe(OH)3 = 106.
86 g / mol
g Fe(OH)3 = 980 g FeCl3 x 1 mol FeCl3 x 1 mol Fe(OH)3 x 106.
86 gFe(OH)3 ```````````````````````` ````````````````````````````` ``````````````````````````````` 162.
20 g FeCl3 1 mol FeCl3 1 mol Fe(OH)3
g Fe(OH)3 = 645.
64.
10g×1mol / (peso molecular del naoh)×L / 2moles = (operas y ya).
Me parece q la respuesta es 08.
% m / m = (m soluto / m solc. ) x 100 %m / m = ( 36 g / 200 g ) x 100 %m / m = 18 %.