Pregunta de Química · 1 respuesta · 3 votos · mejor respuesta de Airampelayo533

En resumen

Zn + 2HCl → ZnCl2 + H2Mm Zn = 65. 39 g / mol ZnCl2 = 136, 28 g / moln ZnCl2 = 61 g Zn x 1 mol Zn x 1 mol ZnCl2 `````````````````` ```````````````````````` 65. 39 g Zn 1 mol Zn n ZnCl2 = 0. 932.

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Airampelayo533
4

Zn + 2HCl → ZnCl2 + H2Mm Zn = 65.

39 g / mol ZnCl2 = 136, 28 g / moln ZnCl2 = 61 g Zn x 1 mol Zn x 1 mol ZnCl2 `````````````````` ```````````````````````` 65.

39 g Zn 1 mol Zn n ZnCl2 = 0.

932.

Preguntas frecuentes

Química?

Zn + 2HCl → ZnCl2 + H2Mm Zn = 65. 39 g / mol ZnCl2 = 136, 28 g / moln ZnCl2 = 61 g Zn x 1 mol Zn x 1 mol ZnCl2 `````````````````` ```````````````````````` 65. 39 g Zn 1 mol Zn n ZnCl2 = 0. 932.