Qué cantidad de dióxido de carbono (CO2) se produce a partir de 5 gramos de propano (CO2) al 97% de pureza y 9 gramos de oxígeno (O2) con pureza del 77%, con un rendimiento de reacción del 94%?

C3H8 + 5 O2 → 3 CO2 + 4 H2OPropano (C3H8) : 5 g al 97 %Oxígeno (O2) : 9 g al 77 %Rendimienti : 94 %Mm CO2 = 44 g / molO2 = 32 g / molcalcular la masa de CO2 = ¿?

1. calcular gramos de O2g O2 = 5 g C3H8 x 1 mol C3H8 x 5 mol O2 x 32 g O2 x 97 g ````````````````````` ```````````````````` ```````````````` `````````````` 44 g C3H8 1 mol C3H8 1 mol O2 100 gg O2 = 17.

632. calcular gramos de C3H8g C3H8 = 9 g O2 x 1 mol O2 x 1 mol C3H8 x 44 g C3H8 x 77 g ``````````````````` `````````````````````` `````````````````````` ```````````` 32 g O2 5 mol O2 1 mol C3H8 100 gg C3H8 = 1.

905Reactivo Llimitante : O23.

Calcular gramos de CO2g CO2 = 9 g O2 x 1 mol O2 x 3 mol CO2 x 44 g CO2 ````````````````` `````````````````````` `````````````````````` 32 g O2 5 mol O2 1 mol CO2g CO2 = 7.

425 (Rendimiento teórico)4.

Calcular gramos de CO2% Rend.

= (Rend.

Real / Rend.

Teórico) x 100despejar Rend.

RealRend.

Real = 94 % x 7.

425 g ````````````````````````````` 100Rend.

Real = 6.

979 g CO2.