Problema de Química fórmula molecular?

P = 250 mmHg / 760 = 0.

328 atm

T = 300 + 273 = 573 K

D = 0.

617 g / l

Datos del CO2

P = 738 / 760 = 0.

971 atm

T = 25 + 273 = 298 K

V = 11.

4 L

Masa de agua = 8.

18 g

Mm = 18 g / mol

CALCULAR MOL DE CARBONO.

P V = n R T

n(mol) = 0.

971 atm x 11.

4 L ````````````````````````````````` 0.

082 (atmL / mol K) 298K

mol = 0.

4245 mol CO2 = 0.

4245 mol C

mol H2O = 8.

18 g x 1 mol x 2 mol H `````````` ```````````` 18 g 1 mol

mol H2O = 0.

9088 = 0.

9088 mol H

g C = 0.

4245 mol C x 12 g C `````````` 1 mol C

g C = 5.

094

g H : 0.

9088 mol x 1 g H ```````` 1 mol H

g H = 0.

9088 g

calcular gramos de oxigeno

g O = (10 - 5.

094 - 0.

9088)g = 3.

997 g O

g O = 3.

997 g x 1 mol O `````````` 16 g O

g O = 0.

2498

dividir cada elemento entre el menor de los resultados

C : 0.

4245 / 0.

2498 = 2

H : 0.

9088 / 0.

2498 = 4

O : 0.

2498 / 0.

2498 = 1

FE : C2H4O

calcular masa molecular de la formula empirica :

C : 2 X 12 = 24 g / mol

H : 4 x1 = 4 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````` Mm FE = 44 g / mol

SE TRABAJA CON LA DENSIDAD PARA CALCULAR LA MASA MOLECULAR Y OBTENER LA MASA MOLECULAR DEL COMPUESTO

P = d x R x T `````````````` Mm

Mm = 0.

617 g / L x 0.

0821(atm L / mol K) x 573 K ```````````````````````````````````````````````````````` 0.

328 atm

Mm = 88 g / mol

n = 88 g / mol / 44 g / mol

n = 2

FM = (C2H4O)2 = C2H8O2.