Por favor AYUDENME CON ESTA TAREADeterminar la masa molecular de los siguientes compuestos1) HNO32) CO23) H3 PO44) HCL5) ZN (CIO)26) CA (OH)27) C6 H12 O68) Bi (NO3)39) Be CO310) H2 Si O3?

1. HNO3

H : 1 x1 = 1 g / mol

N : 1 x 14 = 14 g / mol

O = 3 x16 = 48 g / mol

`````````````````````````````` Mm = 63 g / mol

2)

CO2

c : 1 x 12 = 12 g7mol

O : 2 x 16 = 32 g / mol

```````````````````````````` Mm = 44 g / mol.

3)

H3 PO4

H : 1 x 1 = 3 g / mol

P : 1 x31 = 31 g / mol

O : 4 x 16 = 64 g / mol

`````````````````````````` Mm = 98 g / mol

4)

HCl

h : 1 x 1 = 1 g / mol

Cl : 1 x 35.

4 = 35.

4 g / mol

```````````````````````````````````` Mm = 36.

4 g / mol

5)

Zn(CIO)2

Zn : 1 x 65.

38 = 65.

38 g / mol

Cl : 2 x 35.

4 = 70.

8 g / mol

O : 2 x 26 = 32 g / mol

```````````````````````````````` Mm = 168.

18 g / mol

6)

Ca(OH)2

Ca : 1 x 40 0 40 g / mol

H : 2 x 1 = 2 g / mol

O : 2 x 16 = 32 g / mol

```````````````````````````````` Mm = 74 g / mol

7)

C6 H12 O6

C : 6 x 12 = 72 g / mol

H : 12 x 1 0 12 g / mol

O : 6 x 16 = 96 g / mol

`````````````````````````````` Mm = 180 g / mol

8)

Bi(NO3)3

Bi : 1 x 208, 98 = 208, 98 g / mol

N : 3 x 14 = 42 g / mol

O : 9 x 16 = 144 g / mol

`````````````````````````````````````` Mm = 394.

98 g / mol

9)

BeCO3

Be = 1 x 9 = 9 g / mol

C : 1 x 12 = 12 g / mol

O : 3 x 16 = 48 g / mol

```````````````````````````````` Mm = 69 g / mol

10)

H2SiO3

H : 2 x 1 = 2 g / mol

Si : 1 x 28 = 28 g / mol

O = 3 x 16 = 48 g / mol

`````````````````````````````` Mm = 78 g / mol.