Necesito ayuda urgente con mi tarea de química por favor?

1. C : 52.

2 g / 12 g / mol = 4.

35 mol

O : 34.

8 g / 16 g / mol = 2.

175 mol

H : 13 g / 1 g / mol = 13 mol

dividir entre el menor de los resultados cada elemento

C : 4.

35 mol / 2.

175 mol = 2

O : 2.

175 mol / 2.

175 mol = 1

H : 13 mol / 2.

175 mol = 6

FE : C2H6O

Mm FE

C : 2 x 12 = 24 g / mol

H : 6 x1 = 6 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````` Mm = 46 g / mol

n = 92 g / mol / 46 g / mol = 2

FM = (C2OH6)2 = C4O2H12

2.

Ba : 52.

5 g / 137 g / mol = 0.

383 mol

N : 10.

7 g / 14g / mol = 0.

764 mol

O : 36.

8 g / 16 g / mol = 2.

3 mol

dividir

Ba : 0.

383 mol / 0.

383 mol = 1

N : 0.

764 mol / 0.

383 mol = 2

O : 2.

3 mol / 0.

383 mol = 6

FE : BaN2O6

MmFE

Ba : 1 x 137 = 137 g / mol

N : 2 x 14 = 28 g / mol

O : 6 x 16 = 96 g / mol

`````````````````````````````` Mm = 261 g / mol

n = 261 g / mol / 261 g / mol = 1

FM = (BaN2O6)1 = BaN2O6

3.

1. CALCULAR MOLES de Ca(OH)2 Y DE H3PO4

n Ca(OH)2 = 35 g / 74 g / mol = 0.

473 mol

n H3PO4 = 57 g / 98 g / mol = 0.

582 mol

2.

Calcular mol de Ca3(PO4)2 a partir de los moles calculados

mol Ca3(PO4)2 = 0.

473 mol Ca(OH)2 X 1 mol Ca3(PO4)2 `````````````````````````` 3 mol Ca(OH)2

mol de Ca3PO4)2 = 0.

158 mol

mol Ca3(PO4)2 = 0.

582 mol H3PO4 X 1 mol Ca3(PO4)2 `````````````````````````` 2 mol H3PO4

mol de Ca3PO4)2 = 0.

291 mol

RL : Ca(OH)2.

Es aquel que origina la menor cantidad de moles de producto (0.

158 moles de Ca3(PO4)2)

4.

G MgCl2 = 30 g Mg x 1mol Mg x 1 mol MgCl2 x 95 g MgCl2 ```````````` ```````````````` `````````````````` 24 g Mg 1 mol Mg 1 mol MgCl2

g = 118.

75 g de MgCl2.