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Estructura de lewis para NH3H2OY CH4?

Estructura de lewis para NH3 H2O Y CH4.

Pregunta de Química · 1 respuesta · 1 votos · mejor respuesta de Tefa166

En resumen

NH3 N : 1 x 5 e⁻ = 5 e⁻ H : 3 x 1 e⁻ = 3 e⁻ ``````````````````````````` total = 8 e⁻ . H : N : H `` CH4 C : 1 x 4 e⁻ = 4 e⁻ H : 4 x 1 e⁻ = 4 e⁻ ```````````````````````````` total = 8 e⁻ H .

Respuestas de la comunidad

Mejor respuesta

Tefa166
8

NH3

N : 1 x 5 e⁻ = 5 e⁻

H : 3 x 1 e⁻ = 3 e⁻

``````````````````````````` total = 8 e⁻ .

H : N : H ``

CH4

C : 1 x 4 e⁻ = 4 e⁻

H : 4 x 1 e⁻ = 4 e⁻

```````````````````````````` total = 8 e⁻ H .

H : C : H `` H

H2O

H : 2 x 1 e⁻ = 2 e⁻

O : 1 x 6 e⁻ = 6 e⁻

``````````````````````````` total = 8 e⁻ .

H : O : H ``.

Preguntas frecuentes

Estructura de lewis para NH3H2OY CH4?

NH3 N : 1 x 5 e⁻ = 5 e⁻ H : 3 x 1 e⁻ = 3 e⁻ ``````````````````````````` total = 8 e⁻ . H : N : H `` CH4 C : 1 x 4 e⁻ = 4 e⁻ H : 4 x 1 e⁻ = 4 e⁻ ```````````````````````````` total = 8 e⁻ H .