Escribir la formula y hallar la masa molecular?

. propanona CH3 - C - CH3 C₃H₆O ΙΙ O

Mm de la propanona

C : 3 x 12 = 36 g / mol

H : 6 x 1 = 6 g / mol

O : 1 x 16 = 16 g / mol

``````````````````````````````` Mm = 58 g / mol - 3 - nonanona C₉H₁₈O

₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉

CH3 - CH2 - C - CH2 - CH2 - CH2 - CH2 - CH2 - CH3 ΙΙ O

Mm

C : 9 x 12 = 108 g / mol

H : 18 x 1 = 18 g / mol

O : 1 x 16 = 16 g / mol

``````````````````````````````` Mm = 142 g / mol

.

2 - pentanona C₅H₁₀O

CH3 - C - CH2 - CH2 - CH3 ΙΙ O

Mm

C : 5 x 12 = 60 g / mol

H : 10 x 1 = 10 g / mol

O : 1 x 16 = 16 g / mol

``````````````````````````````` Mm = 86 g / mol

.

8 - metil - 2 - decanona

₁ ₂ ₃ ₄ ₅ ₆ ₇ ₈ ₉ ₁₀

CH₃ - C - CH₂ - CH₂ - CH₂ - CH₂ - CH₂ - CH - CH₂ - CH₃ ΙΙ Ι O CH₃

Mm

C : 11 x 12 = 132 g / mol

H : 22 x 1 = 22 g / mol

O : 1 x 16 = 16 g / mol

`````````````````````````````` Mm = 170 g / mol

.

Butanona C₄H₈O

CH₃ - C - CH₂ - CH₃ ΙΙ O

Mm

C : 4 x 12 = 48 g / mol

H : 8 x 1 = 8 g / mol

O : 1 x 16 = 16 g / mol

`````````````````````````````` Mm = 72 g / mol

.

3 - metil - 2 - butanona

CH3 - C - CH - CH3 ΙΙ Ι O CH₃

Mm

C : 5 x 12 = 60 g / mol

H : 10 x 1 = 10 g / mol

O : 1 x 16 = 16 g / mol

`````````````````````````````` Mm = 86 g / mol

.

5 - hepten - 3 - ona

₁ ₂ ₃ ₄ ₅ ₆ ₇

CH3 - CH2 - C - CH2 - CH = CH - CH3 ΙΙ O

Mm

C : 7 x 12 = 84 g / mol

H : 12 x 1 = 12 g / mol

O : 1 x 16 = 16 g / mol

````````````````````````````` Mm = 112 g / mol

.

4 - pentino - 2, 3 - diona

₁ ₂ ₃ ₄ ₅

CH3 - C - C - C Ξ CH ΙΙ ΙΙ O O

Mm

C : 5 x 12 = 60 g / mol

H : 4 x 1 = 4 g / mol

O : 2 x 16 = 32 g / mol

``````````````````````````````` Mm = 96 g / mol.