Determine la masa molar de las siguientes sustancias a?
Determine la masa molar de las siguientes sustancias a. Gas butano c4h10 b. Acido sulfurico, h2s04 c. Gas hidrogeno, h2.
Determine la masa molar de las siguientes sustancias a. Gas butano c4h10 b. Acido sulfurico, h2s04 c. Gas hidrogeno, h2.
Introduce la fórmula molecular (ej: H2O, NaCl, C6H12O6)
Masa molar18.015 g/mol
H×22.016 g/mol
O15.999 g/mol
En resumen
C4H1O Mm C : 4 x 12 = 48 g / mol H : 10 x 1 = 10 g / mol ```````````````````````````` Mm = 58 g / mol H2SO4 H : 2 x 1 = 2 g / mol S : 1 x 32 = 32 g / mol O : 4 x 16 = 64 g / mol ```````````````````````````` Mm = 98 g / mol H2 H : 2 x 1 = 2 g / mol.
C4H1O
Mm
C : 4 x 12 = 48 g / mol
H : 10 x 1 = 10 g / mol
```````````````````````````` Mm = 58 g / mol
H2SO4
H : 2 x 1 = 2 g / mol
S : 1 x 32 = 32 g / mol
O : 4 x 16 = 64 g / mol
```````````````````````````` Mm = 98 g / mol
H2
H : 2 x 1 = 2 g / mol.
Butano : C4H10 C : 4 x 12 = 48 g / mol H : 10 x 1 = 10 g / mol `````````````````````````````` Mm = 58 g / mol.
C4H10 C : 4 x 12 = 48 g / mol H : 10 x 1 = 10 g / mol ```````````````````````````` Mm = 58 g / mol hidrógeno : H2 H : 2 x 1 = 2 g / mol explicame el sulfurico : esa ?
Butano C4H10 . C = 12 x 4 = 48 ; H = 1x10 = 10. Mm del butano = 58 g / mol C3H14O. C = 12 x 3 = 36 ; H = 1x14 = 14 ; O = 16x1 = 16 . MmC3H14O = 36 + 14 + 16 = 66 g / mol.
1. - Butano (C4H10) C = 12g H = 1g 4(12g) + 10(1g) 48g + 10g = 58g M = 58g / mol 2. - Ácido sulfúrico (H2SO4) H = 1g S = 32g O = 16g 2(1g) + 1(32g) + 4(16g) 2g + 32g + 64g = 98g M = 98g / mol 3. - Hidrógeno molecular…