Cuantos gramos de Argón (Ar) ocuparía un volumen de 25 L a condiciones normales?

Mm Ar = 39.

94 g / mol

1.

Calcular moles de argón 1 mol - - - - 22.

4 L x - - - - 25 L

X = 1 mol x 25 L `````````````````` 22.

4 L

x = 1.

116 mol

2.

Calcular gramos de argón

n = m / Mm

m = 1.

11 mol x 39.

94 g / mol

m = 44.

33 g de Ar

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CN

T = 273 K

P = 1 tm

n = ?

R = 0.

0821 (l atm / mol K)

V = 25 L

Utilizar la fórmula de la ley de los gases

P x V = n x R x T

n = 1 atm x 25 L ```````````````````````````````````````` 0.

0821 (L atm / mol K) x 273 K

n = 1.

11 mol

calcular g de Ar

n = m / Mm

m = 1.

115 mol x 39.

34 g / mol

m = 44.

33 g.