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Como se balancea esta ecuacion •ClO3 - + N2H4 → NO + Cl - por el metodo de ion electron les agradezco gracias?

Como se balancea esta ecuacion •ClO3 - + N2H4 → NO + Cl - por el metodo de ion electron les agradezco gracias.

Calculadora interactiva

ax² + bx + c = 0

Mejor respuesta

9

₊₅ ₋₂ ₋₂ ₊₁ ₊₂₋₂ ₋₁

(ClO3)⁻ + N2H4 → NO + (Cl)⁻ ₊₅ ₋₂ ₋₁ (ClO3)⁻ + 6H2O + 6 e⁻ → (Cl)⁻ + 6(OH⁻) + 3H2O OXIDACCION ₋₂ ₊₁ ₊₂₋₂

N2H4 + 2H2O + 8(OH⁻) → 2NO + 8 H2O + 8e⁻ REDUCCION

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intercambiar electrones ₊₅ ₋₂ ₋₁ (ClO3)⁻ + 6H2O + 6 e⁻ → (Cl)⁻ + 6(OH⁻) + 3H2O 8 e⁻ Ι 2 = 4 ₋₂ ₊₁ ₊₂₋₂

N2H4 + 2H2O + 8(OH⁻) → 2NO + 8 H2O + 8e⁻ 6 e⁻ Ι 2 = 3

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4(ClO3)⁻ + 24 H2O + 24 e⁻ → 4(Cl)⁻ + 24 (OH⁻) + 12 H2O

3N2H4 + 6 H2O + 24 (OH⁻) →6NO + 24 H2O + 24 e⁻

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4(ClO3)⁻ + 3N2H4 → 4(Cl)⁻ + 6NO + 6H2O.