Calculemos el numero de moles que contienen un gas que ocupa un volumen de 3L a 25 grados centigrados de temperatura y740mm de Hg de presion.
En resumen
N (moles) = ? V = 3 L T = 25 + 273 = 298 K P = 740 mmHg 1 atm - - - - 760 mmHg x - - - - 740 mmHg x = 0. 97 atm R = 0. 0821 (atm L / mol K) P x V = n x R x T n = P x V `````````` R x T n = 0. 97 atm x 3 L `````````````````````````````````` O. 0821(atmL / mol K)298K n = 0.
N (moles) = ?
V = 3 L
T = 25 + 273 = 298 K
P = 740 mmHg
1 atm - - - - 760 mmHg x - - - - 740 mmHg
x = 0.
97 atm
R = 0.
0821 (atm L / mol K)
P x V = n x R x T
n = P x V `````````` R x T
n = 0.
97 atm x 3 L `````````````````````````````````` O.
0821(atmL / mol K)298K
n = 0.
118 moles.
V1 P1 / T1 = V2 P2 / T2V1 = . 52LP1 = 650mmhg / 760atm = 0. 855atmT1 = 25C + 273k = 298kV2 = ? P2 = 700mmh / 760atm = 0. 921atmT2 = 32C + 273k = 305kV2 = V1 P1 T2 / T1 P2V2 = (. 52L)(0. 855atm)(305k) / (298k)(0.…
¡Hola! Tenemos los siguientes datos : T1 (temperatura inicial) = 20 ºC (en Kelvin) : TK = TºC + 273, 15 TK = 20 + 273, 15 TK = 293, 15 → T1 (temperatura inicial) = 293, 15 KP1 (presión inicial) = 0, 5 atm V1 (volumen…
Cual es el volumen que ocupa 4 moles con H2 a 12 grados centigrados y 3 atm de presionAplicar la ley de los gases idealesV x P = n x R x Tn = 4 molesP = 3 atmT = 12 ºC + 273 = 285 KR = 0. 0821 (L atm / mol K)calcular…