Calcule los gramos de agua que se deben agregar a 8?
Calcule los gramos de agua que se deben agregar a 8. 50 g de H3PO4 para preparar una solución a 0. 1 molal.
En resumen
Mm H3PO4 = 98 g / mol m = mol soluto ```````````````` Kg svte mol = masa / Mm mol = 8. 5 g / 98 g / mol mol = 0. 086 Kg svte = mol soluto `````````````` m Kg svte = 0. 086 mol ``````````````` 0. 1 mol / Kg svte Kg = 0. 86 de agua g = 0. 86 x 1000 = 860 g de agua.
Mejor respuesta
Mm H3PO4 = 98 g / mol
m = mol soluto ```````````````` Kg svte
mol = masa / Mm
mol = 8.
5 g / 98 g / mol
mol = 0.
086
Kg svte = mol soluto `````````````` m
Kg svte = 0.
086 mol ``````````````` 0.
1 mol / Kg svte
Kg = 0.
86 de agua
g = 0.
86 x 1000 = 860 g de agua.