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- calcule la masa molar de cada una de las siguientes sustancias?

- calcule la masa molar de cada una de las siguientes sustancias. A)perclorato de bario b)sulfato de magnesio c)cloruro de plomo(II) d)nitrato de cobre(II) e)cloruro de estaño(IV) f)fenol, C6H6O g)sulfuro de amonio((NH4)2S h)diclorofenol, C6HOCI2 i)hidruro de bario, BaH2 j)fosfato diacido de potasio, KH2PO4 k)fosfato acido de potasio, K2HPO4 l)fosfato de potasio, K3PO4.

Calculadora interactiva

Introduce la fórmula molecular (ej: H2O, NaCl, C6H12O6)

Masa molar18.015 g/mol

H×22.016 g/mol

O15.999 g/mol

En resumen

A)perclorato de bario = Ba(ClO4)2 Ba : 1 x 137 = 137 g / mol Cl = 2 x 35.

Mejor respuesta

Josiasmb9443
6

A)perclorato de bario = Ba(ClO4)2

Ba : 1 x 137 = 137 g / mol

Cl = 2 x 35.

5 = 71 g / mol

O : 8 x 16 = 128 g / mol

```````````````````````````````` Mm = 336 g / mol

b) MgSO4

Mg : 1 x 24 = 24 g / mol

S : 1 x 32 = 32 g / mol

O : 4 x 16 = 64 g / mol

```````````````````````````` Mm = 120 g / mol

c) PbCl2

Pb : 1 x 207 = 207 g / mol

Cl : 2 x 35.

5 = 71 g / mol

```````````````````````````````` Mm = 278 g / mol

d) Cu(NO3)2

Cu : 1 x 63.

5 = 63.

5 g / mol

N : 2 x 14 = 28 g / mol

O : 6 x 16 = 96 g / mol

```````````````````````````````` Mm = 187.

5 g / mol

e) SnCl4

Sn : 1 x 118.

7 = 118.

7 g / mol

Cl : 4 x 35.

5 = 142 g / mol

```````````````````````````````````` Mm = 260.

7 g / mol

f) C6H6O

C : 6 x 12 = 72 g / mo

H : 6 x 1 = 6 g / mol

O ; 1 x 16 = 16 g / mol

```````````````````````````` Mm = 94 g / mol

g) (NH4)2S

N : 2 x 14 = 28 g / mol

H : 8 x 1 = 8 g / mol

S : 1 X 32 = 32 g / mol

`````````````````````````````` Mm = 68 g / mol

h) C6HOCI2

C : 6 x 12 = 72 g / mol

H : 1 x 1 = 1 g / mol

O : 1 x 16 = 16 g / mol

Cl : 2 x 35.

5 = 71 g / mol

`````````````````````````````````` Mm = 160 g / mol

i) BaH2

Ba : 1 x 137 = 137 g / mol

H : 2 x 1 = 2 g / mol

```````````````````````````````` Mm = 139 g / mol

j) KH2PO4

K : 1 x 39 = 39 g / mol

H : 2 x 1 = 2 g / mol

P : 1 x 31 = 31 g / mol

O : 4 x 16 = 64 g / mol

```````````````````````````````````` Mm = 136 g / mol

k) K2HPO4

K : 2 x 39 = 78 g / mol

H : 2 x 1 = 2 g / mol

P : 1 x 31 = 31 g / mol

O : 4 x 16 = 64 g / mol

```````````````````````````````````` Mm = 175 g / mol

l) K3PO4

K : 3 x 39 = 117 g / mol

P : 1 x 31 = 31 g / mol

O : 4 x 16 = 64 g / mol

```````````````````````````````````` Mm = 212 g / mol.