Calcular las masas de H2O, yO2 con la siguiente ecuacion equilibrada 2C4H10 + 13O2 - - - - - - - - - - - - - - - - 8CO2 + 3H2O si contamos con 150gr de butano ( C4H10).
ax² + bx + c = 0
En resumen
2C4H10 + 13O2 → 8CO2 + 3H2O Mm C4H10 = 58 g / mol H2O = 18 g / mol O2 = 32 g / mola.
2C4H10 + 13O2 → 8CO2 + 3H2O Mm C4H10 = 58 g / mol H2O = 18 g / mol O2 = 32 g / mola.
Calcular gramos de H2Og H2O = 150 g C4H10 x 1 mol C4H1O x 3 mol H2O x 18 g H2O ```````````````````````````` `````````````````````` ``````````````````````` 58 g C4H10 2 mol C4H10 1 mol H2Og H2O = 69.
83b. calcular gramos de O2g O2 = 150 g C4H10 x 1 mol C4H1O x 13 mol O2 x 32 g O2 ```````````````````````````` `````````````````````` ``````````````````````` 58 g C4H10 2 mol C4H10 1 mol H2Og O2 = 537.
93.